How do I print a dictionary in alphabetical order that includes assigned values?

Question

I have this Python Code:

def dictofvalues():
    values = {'A': '1', 'C': '3', 'B': '2'}
    return(values)

def main():
    values = dictofvalues()
    print(sorted(values))

Which prints: A, B, C.

However, I want it to print A:1, B:2, C:3. In other words, I want it to print the item with the assigned value as well.

How does one go about doing this?

If you want it to be sorted on the keys, the easiest/most straightforward way is just to create a for loop: `for key in sorted(values): print("{}: {}".format(key, values[key]))`. — , May 25 '17 at 03:56
Possible duplicate of [How can I sort a dictionary by key?](https://stackoverflow.com/questions/9001509/how-can-i-sort-a-dictionary-by-key) — pvg, May 25 '17 at 03:58
Perhaps equally genius would have been simply searching. It's one of the most answered answers out there. — pvg, May 25 '17 at 04:25

score 0 · Answer 1 · answered May 25 '17 at 04:03

0

Simply print out the dictionary as a list of tuples:

def dictofvalues():
    values = {'A': '1', 'C': '3', 'B': '2'}
    return(values)

def main():
    values = dictofvalues().items()
    print(sorted(values))

answered May 25 '17 at 04:03

A.J. Uppal

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Also works perfectly, no issues here. Thanks for this method, a special thanks for the actual code! :D – Investigative Moth May 25 '17 at 04:09
@InvestigativeMoth no problem, feel free to accept this answer by clicking the green check to give both of us reputation and inform the community that you have found a satisfactory answer – A.J. Uppal May 25 '17 at 04:19

score 0 · Answer 2 · answered May 25 '17 at 07:09

You can use OrderedDict from module collections:

from collections import OrderedDict

def dictofvalues():
    values = {'A': '1', 'C': '3', 'B': '2'}
    return(values)

def main():
    values = dictofvalues()
    print(OrderedDict(sorted(d.items())))

I hope it helps,

How do I print a dictionary in alphabetical order that includes assigned values?

2 Answers2