I have some code that basically do this:
struct Base {
virtual ~Base() = default;
virtual int forward() = 0;
};
struct Derived : Base {
int forward() override {
return 42;
}
};
typename std::aligned_storage<sizeof(Derived), alignof(Derived)>::type storage;
new (&storage) Derived{};
auto&& base = *reinterpret_cast<Base*>(&storage);
std::cout << base.forward() << std::endl;
I highly doubt it's well defined behaviour. If it's indeed undefined behaviour, how can I fix it? In the code that do the reinterpret_cast
, I only know the type of the base class.
On the other hand, if it's well defined behavior in all cases, why is this working and how?
Just keeping a reference to the contained object is not applicable here. In my code I want to apply SBO on a type erased list where the type is created by the user of my library, and basically extends the Base
class.
I add elements inside a template function, but in the function that reads it, I cannot know the Derived
type. The whole reason why I use a base class is because I only need the forward
function in my code that reads it.
Here's what my code looks like:
union Storage {
// not used in this example, but it is in my code
void* pointer;
template<typename T>
Storage(T t) noexcept : storage{} {
new (&storage) T{std::move(t)}
}
// This will be the only active member for this example
std::aligned_storage<16, 8> storage = {};
};
template<typename Data>
struct Base {
virtual Data forward();
};
template<typename Data, typename T>
struct Derived : Base<Data> {
Derived(T inst) noexcept : instance{std::move(inst)} {}
Data forward() override {
return instance.forward();
}
T instance;
};
template<typename> type_id(){}
using type_id_t = void(*)();
std::unordered_map<type_id_t, Storage> superList;
template<typename T>
void addToList(T type) {
using Data = decltype(type.forward());
superList.emplace(type_id<Data>, Derived<Data, T>{std::move(type)});
}
template<typename Data>
auto getForwardResult() -> Data {
auto it = superList.find(type_id<Data>);
if (it != superList.end()) {
// I expect the cast to be valid... how to do it?
return reinterpret_cast<Base<Data>*>(it->second.storage)->forward();
}
return {};
}
// These two function are in very distant parts of code.
void insert() {
struct A { int forward() { return 1; } };
struct B { float forward() { return 1.f; } };
struct C { const char* forward() { return "hello"; } };
addToList(A{});
addToList(B{});
addToList(C{});
}
void print() {
std::cout << getForwardResult<int>() << std::endl;
std::cout << getForwardResult<float>() << std::endl;
std::cout << getForwardResult<const char*>() << std::endl;
}
int main() {
insert();
print();
}