Android | LSB & MSB

Question

I've got problem with LSB and MSB during sending request to the device. I need to send sessionId(int). It needs to be send on four bytes. Right now I'm sending byte array like this :
So , for example if sessionID is 14 I'm sending :

public static final byte[] intToByteArray(int value) {
        return new byte[] {
                (byte)(value >>> 24),
                (byte)(value >>> 16),
                (byte)(value >>> 8),
                (byte)value};
    }


byteData[36] - 0
byteData[37] - 0
byteData[38] - 0
byteData[39] - 14

The problem is - I need to set byteData[36] as LSB and byteData[39] as MSB. Could you help me with this ? Thanks in advance :)

Take a look at [this](https://stackoverflow.com/a/1936865/6950238) answer. — Andrii Omelchenko, May 29 '17 at 08:42
With this solution byteData[39] is still 14. I need value 14 to be on byteData[36] — Bartos, May 29 '17 at 10:25
Just use `ByteOrder.LITTLE_ENDIAN` instead of `ByteOrder.BIG_ENDIAN` order. — Andrii Omelchenko, May 29 '17 at 10:50
Possible duplicate of [Convert integer into byte array (Java)](https://stackoverflow.com/questions/1936857/convert-integer-into-byte-array-java) — David Rawson, May 29 '17 at 11:02

Andrii Omelchenko · Answer 1 · 2017-05-29T11:52:40.860

1

From this answer of Gregory Pakosz with ByteOrder.BIG_ENDIAN to ByteOrder.LITTLE_ENDIAN order change:

ByteBuffer b = ByteBuffer.allocate(4);
b.order(ByteOrder.LITTLE_ENDIAN);
b.putInt(14);
byte[] result = b.array();

In this case b[0] == 14.

edited May 29 '17 at 11:52

answered May 29 '17 at 10:48

Andrii Omelchenko

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Android | LSB & MSB

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