code 1:
int main()
{
char ptr[]="uma";
char *p;
p=ptr;
++*p++;
printf("%s",p);
return 0;
}
code 2:
int main()
{
char *ptr="uma";
++*ptr++;
printf("%s",ptr);
return 0;
}
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`++*p++;` don;t write code like that, parenthesis generally comes for free, you know? – Sourav Ghosh May 29 '17 at 13:40
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An array is **not** a pointer! – too honest for this site May 29 '17 at 13:48
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2@umamahesh In the second program there is an attempt to change a string literal that results in undefined behavior. String literals may not be changed. – Vlad from Moscow May 29 '17 at 13:50
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@SouravGhosh i tried to know precedence and association of increment operators that's why i wrote like that. – umamahesh May 29 '17 at 15:28
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@umamahesh precision? Hows that? Did you mean precedence? – Sourav Ghosh May 29 '17 at 15:29
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i mean array name it self points to first element in array ryt? so we can use it as a pointer . that's why i did. @Olaf – umamahesh May 29 '17 at 15:29
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yeah @SouravGhosh – umamahesh May 29 '17 at 15:31