How to running function that has loop for inside in PHP

Question

I have this code :

$stopwords = array("acara", "ada", "adalah");
foreach ($stopwords as &$word) {
    $word = '/\b' . preg_quote($word, '/') . '\b/';
}

$filter=preg_replace($stopwords, '', $case);

$kata = str_word_count($filter,1);
$jumlah = count($kata);

function myfunction() { 
    for($i=0; $i<$jumlah; $i++){
        echo "$kata[$i]";
    }
}

myfunction();

When I run my code, myfunction doesn't display the output data. How to get output with that function?

This is certainly the most obfuscated code I've seen today. What is your expected output? Why are you passing `$word` by reference? What is `$case`? How is `$stopwords` a pattern? How do you expect myfunction() to have any output when all the variables are out of scope? — Tim Morton, May 31 '17 at 02:26
Your $jumlah inside function is different wth $jumlah outside the function, due to variabl scope. Please read http://php.net/manual/en/language.variables.scope.php — Muhammad Alvin, May 31 '17 at 03:15

score 2 · Accepted Answer · answered May 31 '17 at 02:19

2

You should pass $kata and $jumlah as parameters:

function myfunction($jumlah, $kata) { 
        for($i=0; $i<$jumlah; $i++)
        {
            echo $kata[$i];
        }
}


myfunction($jumlah, $kata);

answered May 31 '17 at 02:19

T. AKROUT

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How to running function that has loop for inside in PHP

1 Answers1