How to remove lookup & share from textview in Swift 3

Question

I can remove cut, copy, paste, select, select all using this

override public func canPerformAction(_ action: Selector, withSender sender: Any?) -> Bool {
    if action == #selector(copy(_:)) || action == #selector(paste(_:)) || action == #selector(selectAll(_:)) || action == #selector(cut(_:))
    {
        return false
    }
    return super.canPerformAction(action, withSender: sender)
}

But I can't remove lookup & Share

Can anyone please suggest me how to remove this?

score 10 · Answer 1 · edited Jun 05 '18 at 17:10

If you really don't want to allow any actions, why do you check for each of them specifically? Just return false in your method. Otherwise, you can place a breakpoint and see what you're getting called with for "action" and add another validation for it

override func canPerformAction(_ action: Selector, withSender sender: Any?) -> Bool {
    print("BlahTextView::canPerformAction: \(action)")
    return false
}

And the result, with the 2 you want removed highlighted:

BlahTextView::canPerformAction: cut: BlahTextView::canPerformAction: copy: BlahTextView::canPerformAction: select: BlahTextView::canPerformAction: selectAll: BlahTextView::canPerformAction: paste: BlahTextView::canPerformAction: delete: BlahTextView::canPerformAction: _promptForReplace: BlahTextView::canPerformAction: _transliterateChinese: BlahTextView::canPerformAction: _showTextStyleOptions: BlahTextView::canPerformAction: _lookup: BlahTextView::canPerformAction: _define: BlahTextView::canPerformAction: _addShortcut: BlahTextView::canPerformAction: _accessibilitySpeak: BlahTextView::canPerformAction: _accessibilitySpeakLanguageSelection: BlahTextView::canPerformAction: _accessibilityPauseSpeaking: BlahTextView::canPerformAction: _share: BlahTextView::canPerformAction: makeTextWritingDirectionRightToLeft: BlahTextView::canPerformAction: makeTextWritingDirectionLeftToRight:

And then you can do:

override public func canPerformAction(_ action: Selector, withSender sender: Any?) -> Bool {
    if action == #selector(copy(_:)) ||
        action == #selector(paste(_:)) ||
        action == #selector(select(_:)) ||
        action == #selector(selectAll(_:)) ||
        action == #selector(cut(_:)) ||
        action == Selector(("_lookup:")) ||
        action == Selector(("_share:")) ||
        action == Selector(("_define:"))
    {
        return false
    }
    return super.canPerformAction(action, withSender: sender)
}

The alternate syntax is required because those methods are not publicly declared and you'll get a compiler error if you use #selector(share(:)) for example.

for lookup - please use ((_define:)) Thanks.

Tried this too. Lookup is not removed. It explains in the docs that other components can say true which will override what is done here. https://developer.apple.com/documentation/uikit/uiresponder/1621105-canperformaction — Jeff Muir, Feb 13 '18 at 23:35
For removing lookup, you need to remove (define) action == Selector(("_define:")) — Neelam Verma, Jun 05 '18 at 17:09

score 2 · Accepted Answer · edited Jun 02 '17 at 13:33

2

// Make sure 
override func canPerformAction(_ action: Selector, withSender sender: Any?) -> Bool {
    if action == #selector(select(_:))
    {
        return true
    } else {
        return false
    }
}

edited Jun 02 '17 at 13:33

answered Jun 02 '17 at 12:52

karthik

159
9

1

if action == #selector(select(_:)) { return true }else{ false } – karthik Jun 02 '17 at 13:02
use this condition – karthik Jun 02 '17 at 13:02
Please user proper format to make every one understood. – Raksha Saini Jun 02 '17 at 13:19

score 2 · Answer 3 · answered Jun 02 '17 at 13:03

As you mentioned in comment of one answer that you want to just enabled select then why don't you compare select and return true for it and false in other case.

override public func canPerformAction(_ action: Selector, withSender sender: Any?) -> Bool {
    if action == #selector(select(_:)) {
        return true
    }
    return false
}

How to remove lookup & share from textview in Swift 3

3 Answers3

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