Pre-condition: list of ints where len(list) >= 2
Post-condition: return the second smallest value. If there exists two smallest values in list, return smallest.
def SecondSmallest(list):
1 smallest = min(list[0], list[1])
2 second_smallest = max(list[0], list[1])
3 i = 2
4 while i < len(list):
5 item = list[i]
6 if item < second_smallest:
7 if item < smallest:
8 second_smallest = smallest
9 smallest = item
10 else:
11 second_smallest = item
12 i += 1
13 return second_smallest
Many Thanks.