Java parse string as date "2017-06-12T14:45:00+05:30"

Question

How do I parse this String in Java as date "2017-06-12T14:45:00+05:30" I've tried using SimpleDateFormat but it is throwing exception. Thanks

Possible duplicate of [Java string to date conversion](https://stackoverflow.com/questions/4216745/java-string-to-date-conversion) — jvwilge, Jun 05 '17 at 12:02
Possible duplicate of [Parsing ISO-8601 DateTime in java](https://stackoverflow.com/questions/16336643/parsing-iso-8601-datetime-in-java) — Ole V.V., Jun 05 '17 at 13:30

score 2 · Accepted Answer · answered Jun 05 '17 at 09:38

It seems to be a valid ISO offset date time format, so this should work without requiring a formatter:

OffsetDateTime date = OffsetDateTime.parse(input);

If you really need a java.util.Date, you can then use:

Date legacyDate = Date.from(date.toInstant());

score 1 · Answer 2 · edited Jun 05 '17 at 09:42

1

DateFormat format = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ssXXX", Locale.ENGLISH);
Date date = format.parse(string);

date is your solution

edited Jun 05 '17 at 09:42

user1516873

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answered Jun 05 '17 at 09:38

Gianfrancesco Aurecchia

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No it says Unparseable date: "2017-06-12T14:45:00+05:30" – dhananjay sengraphwar Jun 05 '17 at 09:46
I recommend you stay away from the long outdated classes like `DateFormat`, `SimpleDateFormat` and `Date`. The modern classes lke `OffsetDateTime` are so much more programmer friendly. An added bonus is the mentioned class parses the ISO 8601 string from the question out of the box with no explicit format. – Ole V.V. Jun 05 '17 at 13:23

score 0 · Answer 3 · answered Jun 05 '17 at 09:40

0

Just provide correct pattern in SimpleDateForamt

    String startDateString = "09/23/2009";
DateFormat df = new SimpleDateFormat("MM/dd/yyyy"); 
Date startDate;
try {
    startDate = df.parse(startDateString);
    String newDateString = df.format(startDate);
    System.out.println(newDateString);
} catch (ParseException e) {
    e.printStackTrace();
}

answered Jun 05 '17 at 09:40

Pradeep Singh

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want to parse "2017-06-12T14:45:00+05:30" – dhananjay sengraphwar Jun 05 '17 at 09:47
1

try pattern like new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ssXXX", Locale.ENGLISH); – Pradeep Singh Jun 05 '17 at 09:49

Java parse string as date "2017-06-12T14:45:00+05:30"

3 Answers3