Object of class GuzzleHttp\Psr7\Request could not be converted to string

Question

I've got an issue for laravel 5.4 when I trying to using guzzleHttp. here is my code.

use GuzzleHttp\Client;
$url = 'http://example.com';
$client = new Client();

$parameter = ['query' => ['name' => 'xxx', 'address' => 'yyy'], 'headers' => [ 'User-Agent' => 'xxxx', 'exceptions' => false, 'timeout' => 10 ]];
$res = $client->request('GET', $url, $parameter);

if ($res->getStatusCode() == 200)
{
 $json = (string)$res->getBody();
 return $json;
}

and I've got this error on log: Error Exception: Object of class GuzzleHttp\Psr7\Request could not be converted to string

what is wrong with my code? please kindly help me. fyi, this error not always happen. sometimes it show this error, sometimes success.

thank you

try this url https://github.com/MatissJanis/oc-mail/commit/e00eb1e4c50df501fd6929c6507f00aaac01b7c5 — Ramzan Mahmood, Jun 07 '17 at 04:36
For me, the problem was that I'd previously accidentally saved to cache a "response" (result of `$client->request()`) instead of using `->getBody()->getContents()`, and so then I kept getting confused when I saw these errors because I thought they were talking about a different Guzzle request, but it was just that I was reading a variable from cache expecting it to be a string, and it was really a response object. — Ryan, Mar 08 '19 at 22:57

score 12 · Accepted Answer · answered Jun 07 '17 at 04:44

12

$json = $res->getBody()->getContents();

try this

answered Jun 07 '17 at 04:44

Exprator

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Farhad Hossen · Answer 2 · 2017-06-08T06:20:27.133

Try this.....

    try {
        $parameter = ['query' => ['name' => 'xxx', 'address' => 'yyy'], 'headers' => [ 'User-Agent' => 'xxxx', 'exceptions' => false, 'timeout' => 10 ]];
        $res = $client->request('GET', $url, $parameter);

        if ($res->getStatusCode() == 200)
          {
             return $res->getBody()->getContents();
          }
    }catch(Exception $e){
        echo 'Caught exception: ',  $e->getMessage();
    }

score 0 · Answer 3 · answered Apr 12 '20 at 09:42

$response = $client->post('http:yanjye.com3', ['phone' => '00','password' => '5555',]);
        if ($response->getStatusCode() == 200){
            $json = (string)$response->getBody();
            return $json;
            }
         var_dump( $response);
         die();


Hello, brother, I think this is the Good way to  which is Working On both  laravel 5.2[larave 5.2]



i have removed Httm 
[laraver 5.2][1]

and use this code :

  [1]: https://laravel.com/docs/7.x/http-client`

Object of class GuzzleHttp\Psr7\Request could not be converted to string

3 Answers3