how to get the days and exact minutes,exact hours from two dates in javascript?

Question

I have start date time and end time,i need to split how many days , hours ,minutes in the two dates

for example , startdatetime = "09-06-2017 10:30" enddatetime = "10-06-2017 11:45"

i need this result : 1 day 1 hour and 15 minutes

I try this one

var t = end - start;
var z = parseInt(t / 1000 / 60);
var time = display(z);
function display(a)
{
    console.log(a);
    var hours = Math.trunc(a/60);
    var minutes = a % 60; 
    var one_day=1000*60*60*24
    var days = Math.ceil(a/one_day)
    var time = [hours,minutes,days];
    return time;
}

i get the following 1day 24 hours and 15 minutes , can anyone help me , if its new logic means i will change into it,thanks in advance

Answer 1

Well, if you look at documentation for javascript Date objects, there is a getTime() method . You can also use the valueOf() method. They both return the number of milliseconds representing your Date object.

You can simply call that on both Date objects and then find the difference. Once you have the difference you can find the amount of secs, mins , hrs, days, etc. Here is an example:

var start = new Date(*some date*);
var end = new Date(*some date*);
var dif = end.valueOf() - start.valueOf();
if (dif >= 0) {
    var secs = Math.floor(dif / 1000 % 60);
    var mins = Math.floor(dif / 1000 / 60 % 60);
    var hrs = Math.floor(dif / 1000 / 60 / 60 % 24);
    var days =
        Math.floor(dif / 1000 / 60 / 60 / 24 % 365);
    var yrs =
        Math.floor(dif / 1000 / 60 / 60 / 24 / 365);

Answer 2

Try the following:

var t = end - start;
var z = parseInt(t / 1000 / 60);
var time = display(z);
function display(minutes)
{
    var hours = (minutes / 60 | 0) % 24;
    var minutes = (minutes | 0) % 60;
    var days = minutes / 60 / 24 | 0;
    return [hours, minutes, days];
}

Note that in javascript, doing x | 0 is the same as Math.floor(x).

Answer 3

It looks to me like your calculation for hours still has the days in it. Once you have established the days, just subtract those out when you calculate the hours.

var start = new Date("June 09, 2017 10:30:00");
var end = new Date("June 10, 2017 11:45:00");
var t = end - start;
var z = parseInt(t / 1000 / 60);
var time = display(z);
console.log(time);
function display(a)
{
    var minutes = a % 60; 
    var one_day=1000*60*60*24
    var days = Math.ceil(a/one_day)
    var hours = Math.trunc((a-(days*1440))/60);
    var time = [hours,minutes,days];
    return time;
}

Having said that, I highly recommend moment.js to handle this type of thing, if you can.

Answer 4

Using momentjs, you can :

• Parse your input string using moment(String, String)
• Parse your input string using moment.utc
• Get difference using diff() function
• Create a duration from the difference value
• Use duration days(), hours(), minutes() to get your result

Here a live sample:

var startdatetime = "2017-06-09T07:00:01.000Z";
var enddatetime = "2017-06-10T09:00:00.000Z";
// Parse input
var mStart = moment.utc(startdatetime);
var mEnd = moment.utc(enddatetime);
// Calculate difference and create duration
var dur = moment.duration( mEnd.diff(mStart) );
// Show the result
console.log(dur.days() + ' days ' + dur.hours() + ' hour ' + dur.minutes() + ' minutes');

<script src="https://cdnjs.cloudflare.com/ajax/libs/moment.js/2.18.1/moment.min.js"></script>

If you want you can use moment-duration-format plug-in to get the same result using format() method on duration. Here a working sample:

var startdatetime = "2017-06-09T07:00:01.000Z";
var enddatetime = "2017-06-10T09:00:00.000Z";
// Parse input
var mStart = moment.utc(startdatetime);
var mEnd = moment.utc(enddatetime);
// Calculate difference and create duration
var dur = moment.duration( mEnd.diff(mStart) );
// Show the result
console.log(dur.format('d [day] h [hour] m [minutes]'));

<script src="https://cdnjs.cloudflare.com/ajax/libs/moment.js/2.18.1/moment.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/moment-duration-format/1.3.0/moment-duration-format.min.js"></script>

Answer 5

var startDateTime = 1497029400000;
var endDateTime = 1497120300000;
var timeDifference = endDateTime - startDateTime
// with the given dates, days equals 1.0520833333333333
// we want to extract the trailing decimal values using modulus to get the other times

function getTimeDifference(timeDifference) {
  var days = timeDifference/1000/60/60/24
  days >= 1 
    ? var dayCount = Math.trunc(days); // store the day count
    : var dayCount = 0; // it is less than one day

  // get the remaining hours
  var hours = (days % 1) * 24;
  var hoursCount = Math.trunc((days % 1) * 24);

  // get the remaining minutes
  var minutesCount = Math.ceil((hours % 1) * 60);
}