Extract substring with a regular expression

Asked Jun 08 '17 at 22:06

Active Jun 08 '17 at 22:06

Viewed 73 times

I want to extract the second folder in a path. The first folder view/ is constant

view/v_os_xxx/my/folder/abc.js
view/v_os_burger/some/other/folder/xyzdf.js

I've read several SO & SuperUser questions though this answer seems to get me close but just cannot seem to eliminate the folders to the right of my target.

Here is what I have thus far: sed -E "s/^view\/(v_os_.*)\/.*$/\1/" which gets me to /v_os_xxx/from/my. I just don't know how to tell sed to stop matching in the group after it encounters the first trailing /

asked Jun 08 '17 at 22:06

Todd

1

Do you mean you want `'s!^view/(v_os_[^/]*)/.*$!\1!'`? – Wiktor Stribiżew Jun 08 '17 at 22:10
1

@Wiktor yes `sed -E "s/^view\/(v_os_[^/]*).*$/\1/"` works! Thanks. – Todd Jun 08 '17 at 22:23
2

echo "view/v_os_xxx/my/folder/abc.js" | awk -F'/' '{print $2}' – skr Jun 08 '17 at 23:18

Extract substring with a regular expression

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