Linux: run in subshell

Question

I want to start a long-running process from a script that then exits, but I'm getting nowhere. Here's my most simple test. With each run, the console is blocked for 5 seconds.

// Create script
me@mine:~/workspace/bin$ cat > test.sh
sleep 5
// Verify script
me@mine:~/workspace/bin$ cat test.sh
sleep 5
// Make executable
me@mine:~/workspace/bin$ chmod 777 test.sh
// Expect to wait
me@mine:~/workspace/bin$ ./test.sh
// Expect to return, still waits
me@mine:~/workspace/bin$ ./test.sh ?
// Ditto
me@mine:~/workspace/bin$ nohup ./test.sh ?
nohup: ignoring input and appending output to 'nohup.out'
me@mine:~/workspace/bin$

I'm running Ubuntu 17.04 64, GNU bash, version 4.4.7(1)-release (x86_64-pc-linux-gnu)

I'm a Linux noob, and I'm sure I'm not getting something. Any help is appreciated.

score 2 · Accepted Answer · answered Jun 09 '17 at 14:07

2

Use ampersand: nohup ./test.sh &

answered Jun 09 '17 at 14:07

phd

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Yeah. It helps to use the correct character. Seriously, thanks for pointing that out. – Steve11235 Jun 09 '17 at 14:53

Alex Mitrus · Answer 2 · 2017-06-09T14:08:15.763

0

Looks like your script is waiting for something. Paste your script in here.

edited Jun 09 '17 at 14:08

answered Jun 09 '17 at 13:41

Alex Mitrus

1
1

How is that different from the `chomd` then execute in the original question, and how will that put `test.sh` in the background? – Eric Renouf Jun 09 '17 at 13:55

score 0 · Answer 3 · answered Jun 09 '17 at 14:20

0

There are a couple ways to do it, my go-to way is by put an ampersand & at the end of the line.

Linux: run in subshell

3 Answers3