Runtime Error Of Scanf();

Question

In following c code scanf is not working. When program is run, it execute upto the second printf line and after it skips the scanf("%c",&sex); and directly execute next printf(). Why this so happen? I run this code on different c compilers, but the output is same.

#include<stdio.h>
void main()
{
  char mar,sex;
  int age,flag=0;

  printf("Married [Y/N]:");
  scanf("%c",&mar);

  printf("Sex [M/F] :");
  scanf("%c",&sex);   //**This not working**

  printf("Age :"); //**execution directly jumped here**
  scanf("%d",&age);

  if(mar=='y')
    flag=1;
  else if(sex=='m'&& age>=30)
    flag=1;
  else if(sex=='f'&& age>=25)
    flag=1;
  else
  {
  }
  if(flag)
  {
    printf("Congratulations!!!! You are Egligible..");
  else
    printf("Sorry... You are not egligible..");

getch();
}

//Output

Married [Y/N]:y
Sex [M/F] :Age :23
Congratulations!!!! You are Egligible..

score 0 · Accepted Answer · answered Jun 09 '17 at 16:09

The problem is with the new line character that you press after you enter values (Y/N) for the previous scanf. The new line character is taken as an input and the program proceeds with the next one. Try to use flushall(); before next read (that is scanf) this will solve your problem. You can also use space before the format specifier to solve this, that will escape the newline character.

Runtime Error Of Scanf();

1 Answers1