HTML within PHP syntax

Question

I'm trying to show a submit button based on a logical statement using PHP and HTML, but I can't figure out the syntax.

if(isset($_POST['newSubmit'])){ 
    <input type="submit" name="newSubmit" id="newSubmit" value="Select" />;    
}

This doesn't seem to work. Do I need to use an echo statement?

[More info about writing html with php](https://stackoverflow.com/questions/18140270/how-to-write-html-code-inside-php) — Foo Bar, Jun 13 '17 at 06:38

B. Desai · Answer 1 · 2017-06-13T06:43:37.790

3

You have to do echo in php or write input outside php

1) echo to display

<?php if(isset($_POST['newSubmit'])){ 
   echo '<input type="submit" name="newSubmit" id="newSubmit" value="Select" />';    
} ?>

2)write html Out side php

<?php if(isset($_POST['newSubmit'])){ ?>
    <input type="submit" name="newSubmit" id="newSubmit" value="Select" />
<?php } ?>

edited Jun 13 '17 at 06:43

answered Jun 13 '17 at 06:39

B. Desai

I think you got the `php`'s opening and closing tag wrong – Carl Binalla Jun 13 '17 at 06:42
@Swellar Its not wrong I have updated only solution from question provided guessing that `php` tag starting at beginning and closed at end of file.Which doest not stated here. BTW I have aded tags – B. Desai Jun 13 '17 at 06:45

score 0 · Answer 2 · answered Jun 13 '17 at 06:40

When generating html in php you need to either use echo or enclose php tags

<?php
if(isset($_POST['newSubmit'])){ 
    echo '<input type="submit" name="newSubmit" id="newSubmit" value="Select" />';    
}
?>

or

<?php
if(isset($_POST['newSubmit'])){?> 
<input type="submit" name="newSubmit" id="newSubmit" value="Select" />    
<?php}?>

2 Answers2