Console crashing after scanf command

Question

Here is the code, he is causing the crashes but he is pretty simple:

int main() {

char* nome;
printf("Digite seu nome:  ");
scanf("%s",&nome);
printf("O nome digitado foi %s \n",nome);

return 0; }

0 warning, but the console crash after I type a simple word.

You may want to allocate some space for that `nome` variable — Federico klez Culloca, Jun 13 '17 at 12:53
[The Definitive C Book Guide and List](https://stackoverflow.com/questions/562303/the-definitive-c-book-guide-and-list) — Stargateur, Jun 13 '17 at 12:53

score 1 · Answer 1 · answered Jun 13 '17 at 12:53

1

nome is an uninitialized pointer, and you're trying to store a string there. But there is no "there", so you get undefined behavior.

Try:

char nome[128];

that will give you some space. This is still dangerous (no limit to how much scanf() will store), but should take you one step further.

answered Jun 13 '17 at 12:53

unwind

1

also `scanf("%s",&nome);` should be `scanf("%s",nome);` (even if it works with a char array) – Jean-François Fabre Jun 13 '17 at 12:54
I bought a beginner book and he said the other way to me, people are fast to say "read a book" even if you're trying, for example, @SouravGhosh is the least helpful user in this site. I will try to buy another book. – Rodrigo H Jun 13 '17 at 12:57

1 Answers1