React Native Open settings through Linking.openURL in IOS

Question

I want to open ios setting app from my app. the settings destination is [ settings => notification => myapp ]. to turn on & turn off push notification.

There are some documents about how to link to settings, but I don't know how to open deep link. (notification => myapp).

How can I do this?

score 37 · Accepted Answer · answered Jun 16 '17 at 07:04

37

You can deep-link referencing the settings's index like so:

Linking.openURL('app-settings:')

Above method only for IOS

answered Jun 16 '17 at 07:04

Arunkumar

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9

Thanks. I can do it with `Linking.openURL('app-settings://notification/myapp')}` – ton1 Jun 20 '17 at 02:51
4

Is there any solution for android which does not require an external lib? – Pavan Nov 17 '17 at 11:08
6

@Arunkumar Do you know the equivalent for Android? – wcandillon Nov 27 '17 at 15:16
@wcandillon sry I don't know, I'll check and let you know – Arunkumar Nov 28 '17 at 07:14

B. Mohammad · Answer 2 · 2023-03-20T17:13:54.940

34

Since React Native 0.60 to open App settings use:


import { Linking } from 'react-native';

Linking.openSettings();

Open the app’s custom settings, if it has any.

Works for Android and iOS

Docs link: https://reactnative.dev/docs/linking#opensettings

edited Mar 20 '23 at 17:13

answered Sep 20 '19 at 10:48

B. Mohammad

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1

is there way to open the Location permistion setting directly? – Oliver D Apr 23 '20 at 15:23
1

try this `Linking.openURL('App-Prefs:LOCATION_SERVICES')` – B. Mohammad Apr 23 '20 at 15:31
I got this error `Could not open URL 'App-Prefs:LOCATION_SERVICES': No Activity found to handle Intent { act=android.intent.action.VIEW dat=app-prefs:LOCATION_SERVICES flg=0x10000000 }` – Oliver D Apr 23 '20 at 16:15
1

Ah sorry this is for ios. For android i use this library 'react-native-settings' – B. Mohammad Apr 23 '20 at 16:48
This did not work for me – Tushar Shahi Mar 19 '23 at 11:27
@TusharShahi verify your code again, here is the docs for it: https://reactnative.dev/docs/linking#opensettings – B. Mohammad Mar 20 '23 at 17:11

score 5 · Answer 3 · answered Oct 02 '18 at 10:36

Use Linking.openURL. For example, below is how to check and open Health app on iOS

import { Linking } from 'react-native'

async goToSettings() {
  const healthAppUrl = 'x-apple-health://'
  const canOpenHealthApp = await Linking.canOpenURL(healthAppUrl)
  if (canOpenHealthApp) {
    Linking.openURL(healthAppUrl)
  } else {
    Linking.openURL('app-settings:')
  }
}

score 5 · Answer 4 · answered May 26 '21 at 09:35

5

for iOS 14, this is how i open location service settings

Linking.openURL('App-Prefs:Privacy&path=LOCATION')

tested in react native 0.63.4

answered May 26 '21 at 09:35

Abid Khairy

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score 2 · Answer 5 · answered Jul 26 '17 at 16:22

2

To access specific settings screens, try this: Linking.openURL("App-Prefs:root=WIFI"); Linking to app-settings only opens the settings for the Reference: iOS Launching Settings -> Restrictions URL Scheme (note that prefs changed to App-Prefs in iOS 6)

answered Jul 26 '17 at 16:22

Julian K

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has anyone else tried this? unfortunately it did not work for me on iOS 11 (both simulator and real device) – Antoni4 Mar 14 '18 at 16:18
Hey, thanks in my case 'App-Prefs:root' works for me – Nald Dev Jul 06 '20 at 13:10
1

as of iOS 14, what's working for me is Linking.openURL("App-prefs:General") - just remove `root=` from examples that have it – jes5199 Dec 02 '20 at 23:44
Linking.openURL('App-Prefs:ACCESSIBILITY'); is working. for me – Ani David May 18 '22 at 08:06

score 1 · Answer 6 · edited Jan 14 '21 at 05:49

1

Try this one for Open Specific System URL - Linking.openURL('App-Prefs:{3}')

edited Jan 14 '21 at 05:49

Sabito stands with Ukraine

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answered May 11 '19 at 08:08

Karan Prajapati

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score -1 · Answer 7 · answered Jan 06 '21 at 15:38

-1

try this

Linking.openURL('app-settings://notification/myapp')

answered Jan 06 '21 at 15:38

Govan

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I tried and it doesn't work :( – DAVID _ Jul 27 '22 at 15:43

React Native Open settings through Linking.openURL in IOS

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