Accessing original name of file uploaded as a file parameter

Question

I have a simple parametrized Jenkins job that takes a file parameter. However when I try to get its original name in the build step I get a bad substitution error on bash.

Here is the file param

Here is the build step

Here are the instructions on getting the name

The error message I get is:

00:00:00.007 /tmp/jenkins4136900049932701838.sh: 2: /tmp/jenkins4136900049932701838.sh: Bad substitution
00:00:00.011 Build step 'Execute shell' marked build as failure

This is more of a bash question than a Jenkins question, but I wanted to give context to what I am doing.

Any suggestions why I am not able to dereference the variable ?

score 1 · Accepted Answer · answered Jun 16 '17 at 18:15

1

The problem here is that your file name does not contain valid characters to be created as a variable.

"." nor "/" are not valid characters in a bash variable so the system cannot save your file name as a variable.

See also since this has been answered before: Access file parameter in jenkins

answered Jun 16 '17 at 18:15

stobiewankenobi

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In that case the Jenkins help documentation is wrong because they give precisely that example. ${abc.zip}, see screenshot in my post above. – Ankur Agarwal Jun 16 '17 at 21:28
haha, well if there can be one thing said of jenkins, their documentation generally is shit. – stobiewankenobi Jun 16 '17 at 21:43

Accessing original name of file uploaded as a file parameter

1 Answers1