Find 1 of 3 characters in a string

Question

I have to find 1 of 3 characters in a string. How can I do that?

I tried this:

let value = "from 3,95 €"
let wanted: Character = "£", "€" OR "₹"
if let idx = value.characters.index(of: wanted) {                                    
    print("Found \(wanted)")
} else {
    print("Not found")
}

Thank you!

You just want to check String having that character or not, right or you want index of that character also ? — Nirav D, Jun 19 '17 at 06:16
Any reason for why you don't use `NSNumberFormatter`? Check this [documentation](https://developer.apple.com/documentation/foundation/numberformatter). — LinusGeffarth, Jun 19 '17 at 06:16
@Nirav D: Yes, i just want to check if one of these characters in a string or not. No i don't need the index.... — Saintz, Jun 19 '17 at 06:21
@Saintz see [my answer](https://stackoverflow.com/a/44623471/3687801) below — nayem, Jun 19 '17 at 06:42
Possible duplicate of [What is the best way to determine if a string contains a character from a set in Swift](https://stackoverflow.com/questions/28486138/what-is-the-best-way-to-determine-if-a-string-contains-a-character-from-a-set-in) — nayem, Jun 19 '17 at 07:01

Nirav D · Accepted Answer · 2017-06-19T06:27:43.293

1

Don't exactly know what you want achieve but if you want to know which character string contains from these 3 character then you can make something like this.

let value = "from 3,95 €"
let wanted: [Character] = ["£", "€", "₹"]
if let result = value.characters.first(where: { wanted.contains($0) }) {
    print("Found \(result)")
} else {
    print("Not found")
}

Output

Found €

Edit: If you just want to check the string contains then use contains(where:) instead of first(where:)

if value.characters.contains(where: { wanted.contains($0) }) {
    print("Found")
} else {
    print("Not found")
}

edited Jun 19 '17 at 06:27

answered Jun 19 '17 at 06:22

Nirav D

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I just want to check if one of these characters in a string or not. No i don't need the index.... – Saintz Jun 19 '17 at 06:25
contains(where:) won't help: They say : Fix it : delete "where:" – Saintz Jun 19 '17 at 06:41
@Saintz Both the code perfectly compiling and running on my side can you show what you are trying, also check once again that you are trying exactly same code that I have added – Nirav D Jun 19 '17 at 06:44
@Saintz Welcome mate :) – Nirav D Jun 19 '17 at 06:49

score 1 · Answer 2 · answered Jun 19 '17 at 06:47

1

Swift 3:

if let dataArray = value.characters.filter{ $0 == "£" || $0 == "€" || $0 == "₹" }, dataArray.count > 0 {
//you have at least one of them in your string, so do whatever you want here
}

answered Jun 19 '17 at 06:47

Mina

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Sorry, one more question. And if i want to find no one of these characters in the string is it ??? : !value.characters.filter{ $0 == "£" || $0 == "€" || $0 == "₹" }, dataArray.count > 0 {... – Saintz Jun 19 '17 at 06:54
you can use ```else {}``` statement. ```if let dataArray = ... > 0 {} else {//None of them found}``` – Mina Jun 19 '17 at 07:01

score 0 · Answer 3 · answered Jun 19 '17 at 06:21

0

Try this if you want to just determine whether they exists or not:

let value = "from 3,95 €"
let wanted = CharacterSet(charactersIn: "£€₹")
if value.rangeOfCharacter(from: wanted) != nil {
    print("Found")
} else {
    print("Not found")
}

answered Jun 19 '17 at 06:21

nayem

7,285
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Find 1 of 3 characters in a string

3 Answers3