Get modules in a module - Python

Question

I have this structure:

project/
    sources/
        __init__.py
        source_one.py
        source_teo.py
    main.py

Then in main.py

import sources

# Here I'd like to get a list with [source_one, source_two]

Then import them dinamycally.

Is there any way to get this?

EDIT

What I get from dir(sources):

if I do import sources I get ['__author__', '__builtins__', '__doc__', '__file__', '__name__', '__package__', '__path__']

If I do from sources import * I get ['__author__', '__builtins__', '__doc__', '__file__', '__name__', '__package__', '__path__']

If I do from sources import source_one I get ['__author__', '__builtins__', '__doc__', '__file__', '__name__', '__package__', '__path__', 'source_one']

But, I don't know the name of files in sources package, this is only an example. How can I find them?

Possible duplicate of [How do to multiple imports in Python?](https://stackoverflow.com/questions/3260599/how-do-to-multiple-imports-in-python) — Easton Bornemeier, Jun 20 '17 at 21:19
@RaminNietzsche Using `*` I could use `source_one` and `source_teo`. In this example, but I don't know what file will be in `sources`, so, sin I can not use them by name I need to get them dinamically in a list. — Gocht, Jun 20 '17 at 21:19
`dir(sources)` should tell you what's in there, and `source1 = __import__("source1", fromlist=(sources,))` should do the rest — inspectorG4dget, Jun 20 '17 at 21:22
@RaminNietzsche: Unless `sources` puts in extra work to support it, no, that actually doesn't work. Importing `*` from a package won't automatically load its submodules. — user2357112, Jun 20 '17 at 21:23
@RaminNietzsche I need the name to use `exec` the problem here is find the names of files in `sources` — Gocht, Jun 20 '17 at 21:30
Don't use `exec` - `__import__` should suffice (see my earlier comment) — inspectorG4dget, Jun 21 '17 at 14:29

Gefen Morami · Answer 1 · 2017-06-20T21:45:40.843

1

you should import relative to the current file location

Example :

from sources.source_one import ClassSourceOne
from sources import *

In example 2, you can call the classes only by name_of_module.ClassName

Or you can use dynamicly import as shown here : import dynamicly from package

Also I recommend to import only the classes/modules you use that's why I recommend

from module import Class

And not using import * so it import all the module dependencies too

edited Jun 20 '17 at 21:45

answered Jun 20 '17 at 21:22

Gefen Morami

313
1
5

Thanks, but I don't know the name of python files in `sources` that's why this should work dynamically. – Gocht Jun 20 '17 at 21:29
To use classes in `source_one` by calling only `sources` -> `sources.Class_in_source_one` I need to add `from source_one import Class_in_source_one` in `__init__.py`. But, once again, I do not know the name of files in `sources` – Gocht Jun 20 '17 at 21:36

score 1 · Accepted Answer · answered Jun 20 '17 at 21:31

1

It's kind of trick ;) but works:

import os
fileslist = os.listdir("sources")
for item in fileslist:
    if item.endswith("py") and item != "__init__.py":
        exec ("from sources.%s import *" %(item.split('.')[0]))

answered Jun 20 '17 at 21:31

RaminNietzsche

2,683
1
20
34

Get modules in a module - Python

EDIT

2 Answers2