raspberry pi can't make any url requests, connection timed out

Question

I need to update my sensor data to thingspeak , so I was doing it with the python thingspeak library. Two days ago it was working fine but now it doesn't work, the connection times out , I also tried to update it with urllib2 ,that too doesnt' work.

My net connection is fine, I am able to open webpages on Pi and I can update the channel from my laptop using thingspeak library as well as urllib2. could someone kindly help me.

my code with thingspeak library:

node = False
channel_id = ""
write = ""
if data['MAC'] in ':ab:35':
 channel_id = "XXXXX"
 write = "XXXXXXXXXXX"
 node = True

if node:
 channel = thingspeak.Channel(id=channel_id,write_key=write)
 try :
     response=channel.update({1:data['TEMP'],2:data['VOLT'],3:data['PRES'],4:data['HUM']})
    print response
    print 'Thingspeak updated!!!'
 except :
    print "connection failed"

when i try urllib2 :

f = urllib2.urlopen(url)
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "/usr/lib/python2.7/urllib2.py", line 154, in urlopen
    return opener.open(url, data, timeout)
  File "/usr/lib/python2.7/urllib2.py", line 431, in open
  response = self._open(req, data)
  File "/usr/lib/python2.7/urllib2.py", line 449, in _open
  '_open', req)
  File "/usr/lib/python2.7/urllib2.py", line 409, in _call_chain
  result = func(*args)
  File "/usr/lib/python2.7/urllib2.py", line 1240, in https_open
  context=self._context)
  File "/usr/lib/python2.7/urllib2.py", line 1197, in do_open
  raise URLError(err)
  urllib2.URLError: <urlopen error [Errno 110] Connection timed out>

when I try thingspeak library :

>>> channel = thingspeak.Channel(id=c,write_key=w)
>>> res = channel.update({1:50,2:30,3:70,4:20})
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "build/bdist.linux-armv7l/egg/thingspeak/thingspeak.py", line 116,         in update
  File "/usr/lib/python2.7/dist-packages/requests/api.py", line 94, in post
    return request('post', url, data=data, json=json, **kwargs)
  File "/usr/lib/python2.7/dist-packages/requests/api.py", line 49, in request
    return session.request(method=method, url=url, **kwargs)
  File "/usr/lib/python2.7/dist-packages/requests/sessions.py", line 457, in request
    resp = self.send(prep, **send_kwargs)
  File "/usr/lib/python2.7/dist-packages/requests/sessions.py", line 569, in send
    r = adapter.send(request, **kwargs)
  File "/usr/lib/python2.7/dist-packages/requests/adapters.py", line 407, in send
    raise ConnectionError(err, request=request)

requests.exceptions.ConnectionError: ('Connection aborted.', error(110, 'Connection timed out'))

I did some tcp socket programming on it yesterday and used a lot of ports, is that somehow responsible for the error ? — Pratik Kumar, Jun 22 '17 at 09:50

Anoroah · Answer 1 · 2017-06-22T09:15:48.790

I am using the raspberry-pi to send data to thingspeak. What I do is something like this:

import httplib
import urllib

    #Preparing to send the information to the cloud
            params=urllib.urlencode({'field1':liters,'key':key})
            headers={"Content-typZZe": "application/x-www-form-urlencoded","Accept":"text/plain"}
            conn=httplib.HTTPConnection("api.thingspeak.com:80")

    #Sending the data to the thingspeak platform
            try:
                    conn.request("POST", "/update", params, headers)
                    response=conn.getresponse()
                    print response.status, response.reason
                    data=response.read()
                    conn.close()
            except:
                    print "connection failed"

And it works just fine. The key is the string of your channel key.

Hope it helps.

Well it works in my device. Try to see if you network blocks this connection. For example port 80. — Anoroah, Jun 22 '17 at 09:23

score 0 · Accepted Answer · answered Jun 27 '17 at 11:38

0

If I use SSH and try to run the script, it works .

answered Jun 27 '17 at 11:38

Pratik Kumar

2,211
1
17
41

score -1 · Answer 3 · answered Jun 22 '17 at 08:33

-1

Add a new User-Agent, by creating Request objects & using them as arguments for urlopen:

import urllib2

request = urllib2.Request('http://www.example.com/')
request.add_header('User-agent', 'Mozilla/5.0 (Linux i686)')

response = urllib2.urlopen(request)

answered Jun 22 '17 at 08:33

DreamInBox

174
2
12

Why not ??? urllib2 respects robots.txt and many sites block the default User-Agent. By the way, connect timed out may from ports is closed. If not from User-Agent, you can consider some port if not open – DreamInBox Jun 22 '17 at 08:43
It did not help, gives urllib2.URLError: – Pratik Kumar Jun 22 '17 at 08:55
f = urllib2.urlopen(url). What is your url ? It is http or https – DreamInBox Jun 22 '17 at 09:36
I see your web domain is https. Your connection is https so you must use ssl cetification.You can see:https://stackoverflow.com/questions/2146383/https-connection-python – DreamInBox Jun 23 '17 at 01:07

raspberry pi can't make any url requests, connection timed out

3 Answers3