Java Extracting Characters and Integers from String

Asked Jun 22 '17 at 07:51

Active Jun 22 '17 at 07:51

Viewed 24 times

I have this method that receives a string that contains an integer at the end, i've tried to extract the characters and the integer this way:

public void findCardPosition(String cardLocation,ImageView cardImage){
        String cardName = null;
        String cardType = cardLocation.replaceAll("[^a-z]","");
        String cardPosition = cardLocation.replaceAll("[^0-9]", "");
        int position = Integer.parseInt(cardPosition)-1;
        if(cardType=="territory"){
            cardName=GameBoard.getTerritoryTower().placeTowerTerritories().get(position).getName();
        }

        if(cardLocation=="territory1"){
            cardName=GameBoard.getTerritoryTower().placeTowerTerritories().get(position).getName();
        }
        if(cardName!=null){
            this.findCardImage(cardName,cardImage);
        }
    }

In theory both IF should work but the first one doesn't which means that when i apply String cardType = cardLocation.replaceAll("[^a-z]",""); to the string "territory1" it doesn't return the string "territory". The string cardPositionworks, so i don't understand why the stringcardTypedoesn't.

asked Jun 22 '17 at 07:51

mark119

cardType=="territory" – ΦXocę 웃 Пepeúpa ツ Jun 22 '17 at 07:52
2

never ever in java – ΦXocę 웃 Пepeúpa ツ Jun 22 '17 at 07:52
Use `equals()` or `contains()` instead to compare strings in Java. Also, a java String is immutable. What is returned by `String.replaceAll()` is a copy. – patrik Jun 22 '17 at 08:19

Java Extracting Characters and Integers from String

0 Answers0