Why the float values are different from double values when set precision?

Asked Jun 23 '17 at 09:03

Active Jun 23 '17 at 09:14

Viewed 71 times

Why the float values are different from double values when set precision on std::cout ??

    std::cout << std::setprecision(20) << endl;
    float num = 1.2;
    cout <<  num << endl;
    double num2 = 1.2;
    cout <<  num2 << endl;

Output:

1.2000000476837158203
1.1999999999999999556

edited Jun 23 '17 at 09:09

Jarod42

asked Jun 23 '17 at 09:03

Hatem Safwat

2

Will it be 'cause the math-precision of the float is different from the double? Double: https://en.wikipedia.org/wiki/Double-precision_floating-point_format Float: https://en.wikipedia.org/wiki/Single-precision_floating-point_format – Sir Jo Black Jun 23 '17 at 09:05
@moooeeeep: Damn, that's a better duplicate. Shall I reopen, and you close as dupe to that one? – Bathsheba Jun 23 '17 at 09:09
According to the story I would say more than double is super-set of float! ;) – Sir Jo Black Jun 23 '17 at 09:11
1

I've reopened, so someone can close against the other duplicate. – Bathsheba Jun 23 '17 at 09:14
Different isn't the same. -- Fred Picker – Pete Becker Jun 23 '17 at 14:49

0 Answers0