Docker compose wait for without sleep command

Question

I've read lots for similar topics; For example this: Docker Compose wait for container X before starting Y etc.

So, I'm trying to implement a wait for only using compose and health checks.

I have only one docker-compose file. There is a section for the app and for test for this app.

Test (service) can be executed only when app(jar, db etc) will be ready. Also after test (service) execution, I want to get status for this execution via $?

So my compose file is next:

version: "2.1"
networks:
  myNetwork:
services:
  rabbitmq:
   ... 
    networks:
      - myNetwork
    healthcheck:
      test: ["CMD", "rabbitmqctl", "status"]
      interval: 100s
      timeout: 10s
      retries: 10
  app:
    ...
    depends_on:
      rabbitmq:
        condition: service_healthy
    networks:
      - myNetwork
    healthcheck:
      test: ["CMD", "wget", "http://localhost:8080/ping"]
      interval: 100s
      timeout: 10s
      retries: 10

  tests:
    build:
      context: .
      dockerfile: TestDocker
    depends_on:
      app:
        condition: service_healthy
    networks:
      - myNetwork

Im trying to run:

docker-compose up -d app && docker-compose run tests;

or

docker-compose run tests

But docker-compose run tests don't waits for condition: service_healthy; (app and rabbitmq containers is started but service_healthy was not checked);

And this is the problem.

When I do something like this:

  docker-compose up -d app && sleep 20 && docker-compose run tests;

So is there is any possibility to do sleep or wait for, for command: docker-compose run tests ?