PHP cannot load image and display it

Asked Jun 26 '17 at 11:03

Active Jun 26 '17 at 11:03

Viewed 1,000 times

I am trying to make a php script to load image and display it depending on $_GET paramters.

I want to use this later to load image into my mobile application(Android).

The problem is I cannot make image to display. I use the code below:

header("Content-Type: image/jpeg");
readfile($path);

But when I open page in firefox I get error:

Image cannot be displayed because it contains errors.

What is more I tried different approach and I can get image display in html code(I dont want this - it requires to remove headers in java android - but it proves that path is correct)

echo '<img src="data:image/jpeg;base64,'.base64_encode(file_get_contents($path) ).'"/>

What am I doing wrong? Any ideas? Thanks in advance.

asked Jun 26 '17 at 11:03

Alek

1

Is there any output before? – Bernhard Jun 26 '17 at 11:11
Ensure that you do not output any characters before the header is sent! Also see: https://stackoverflow.com/questions/3385982/the-image-cannot-be-displayed-because-it-contains-errors – user1915746 Jun 26 '17 at 11:12
I only see error, which means that header is included correcly and my browser tries to open page as image. – Alek Jun 26 '17 at 11:14
@Alek you must check the output – Neodan Jun 26 '17 at 11:25
Ok, I got a space at the begining. That might be a problem – Alek Jun 26 '17 at 11:53
1

There was a space in a file where I connected to mysql database to verify paramters. Removed it and it works. – Alek Jun 26 '17 at 12:03

PHP cannot load image and display it

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