How do I get all item of an array which doesn't exists in another array

Question

How can get all the items of array which do not exists another array?

I have one array with already selected values:

var selectedList = [1,2];

Another array with list of Objects like

var objList = [{Value:1, Name:'KL'},{Value:2, Name:'XYZ'},{Value:3, Name:'ABC'}];

I wanted result to be filter on value field of ObjList array and only those records come which do not exists in the selectedList.

And show example of arrays. Much simpler for one dimensional arrays of primitives than nested arrays or arrays of objects — charlietfl, Jun 27 '17 at 10:55

user93 · Accepted Answer · 2017-06-27T11:12:09.377

1

You could use simple filter to do that

var selectedList = [1, 2];
var objList = [{
  Value: 1,
  Name: 'KL'
}, {
  Value: 2,
  Name: 'XYZ'
}, {
  Value: 3,
  Name: 'ABC'
}];

var data = objList.filter(x => selectedList.indexOf(x.Value) != -1)

console.log(data)

edited Jun 27 '17 at 11:12

answered Jun 27 '17 at 10:56

user93

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score 0 · Answer 2 · answered Jun 27 '17 at 10:56

0

You can try:

var bigArray = ['a', 'b', 'c', 'd', 'e', 'f', 'g'];
var smallArray = ['b', 'c', 'g'];

var newArray = bigArray.filter( function(item) {
  return smallArray.indexOf(item) < 0;
});

or if using underscore.js use .difference()

answered Jun 27 '17 at 10:56

Martin Shishkov

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5
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44

How do I get all item of an array which doesn't exists in another array

2 Answers2