splitting a sequence into pair combinations

Question

Apologies if I do not frame my question well, I'll try my best to do so:

How can I get a list to return every possible pair combination within it?

for instance

a = [1,2,3,4]

I would like to know how I can obtain a result like this:

a= [ [1,2], [1,3] , [1,4], [2,3] , [2,4] , [3,4] ]

Duplicate: https://stackoverflow.com/questions/2541401/pairwise-crossproduct-in-python — Alex, Jun 27 '17 at 14:26

Keerthana Prabhakaran · Accepted Answer · 2017-06-27T14:32:37.877

1

You can make use of combinations in itertools modules!

>>> import itertools as it
>>> it.combinations([1,2,3,4],2)
<itertools.combinations object at 0x106260fc8>
>>> list(it.combinations([1,2,3,4],2))
[(1, 2), (1, 3), (1, 4), (2, 3), (2, 4), (3, 4)]

edited Jun 27 '17 at 14:32

answered Jun 27 '17 at 14:27

Keerthana Prabhakaran

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thanks, I shall have to look into the whole itertools module, seems really useful – czolbe Jun 27 '17 at 14:41

score 0 · Answer 2 · answered Jun 27 '17 at 14:26

0

>>> import itertools
>>> a = [1,2,3,4]
>>> list(itertools.combinations(a, 2))
[(1, 2), (1, 3), (1, 4), (2, 3), (2, 4), (3, 4)]

answered Jun 27 '17 at 14:26

Kevin

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splitting a sequence into pair combinations

2 Answers2