unexpectedly found nil while unwrapping an Optional value parsing json swift

Question

I try to parse json with swift using following:

   let apiPath = "http://samples.openweathermap.org/data/2.5/forecast?q=München,DE&appid=b1b15e88fa797225412429c1c50c122a1"

    func getDataWithCompletionHandler(completionHandler: (_ jsonData: JSON?) -> Void) {


        let request : URLRequest = URLRequest(url: URL(string: apiPath)!)

 Alamofire.request(apiPath, method: .get)
            .responseJSON { (response) in

When my app running i got an error on line:

let request : URLRequest = URLRequest(url: URL(string: apiPath)!)

fatal error: unexpectedly found nil while unwrapping an Optional value.

But i did pass correct string. Why is that error happen?

Remove this line from code.let request : URLRequest = URLRequest(url: URL(string: apiPath)!) — Brijesh Shiroya, Jun 29 '17 at 05:46
@UsamaSadiq why? please try it and you will find json response. — Evgeniy Kleban, Jun 29 '17 at 05:48
can you post complete code? I mean with complete brackets. i just want test exactly — Usama Sadiq, Jun 29 '17 at 05:53
Issue is special character, and due to special character apiPath is not proper string, so URL is giving nil. — Usama Sadiq, Jun 29 '17 at 05:56

score 1 · Answer 1 · answered Jun 29 '17 at 05:52

Try this code:

Alamofire.request(“http://samples.openweathermap.org/data/2.5/forecast?q=München,DE&appid=b1b15e88fa797225412429c1c50c122a1”, method: HTTPMethod.get, parameters:nil , encoding: URLEncoding.default, headers: nil).validate().responseJSON { (response) in
           if response.result.isSuccess
           {
        //handle response
           }
       }

score 1 · Answer 2 · answered Jun 29 '17 at 05:54

1

You string content not correct symbol "ü" in this path "q=München".

Replace it to correct symbol "u".

answered Jun 29 '17 at 05:54

Citrael

542
4
17

Nirav D · Accepted Answer · 2017-06-29T05:57:25.613

Your URL string contains special characters so what you need to do is encode your URL string before making URL object from it. There is two way to encode the URL string.

Using addingPercentEncoding(withAllowedCharacters:)

let apiPath = "http://samples.openweathermap.org/data/2.5/forecast?q=München,DE&appid=b1b15e88fa797225412429c1c50c122a1"
if let encodeString = apiPath.addingPercentEncoding(withAllowedCharacters: CharacterSet.urlQueryAllowed),
   let url = URL(string: encodeString) {
     print(url)
}

Using URLComponents

var urlComponent = URLComponents(string: "http://samples.openweathermap.org/data/2.5/forecast")!
let queryItems = [URLQueryItem(name: "q", value: "München,DE"), URLQueryItem(name: "appid", value: "b1b15e88fa797225412429c1c50c122a1")]
urlComponent.queryItems = queryItems
print(urlComponent.url!)

unexpectedly found nil while unwrapping an Optional value parsing json swift

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