Sort the list L by the ratio of the elements in the 2-tuples in place

Question

I am trying to sort the list L by the ratio of the elements in the 2-tuples.

Parameters
----------
L : {list} of 2-tuples ({tuple}) of {int}

Returns
-------
None   

Example
-------
>>> L = [(2, 4), (8, 5), (1, 3), (9, 4), (3, 5)]
>>> sort_by_ratio(L)
>>> L
[(1, 3), (2, 4), (3, 5), (8, 5), (9, 4)]

So far I have

L[:] = sorted(L,key = lambda ratio: ratio[0]/ratio[1])

but it somehow gave me a list of [(2, 4),(1, 3),(3, 5), (8, 5), (9, 4)]

Where did I do wrong?

`/` for ints is floor division on Python 2. – user2357112 Jun 30 '17 at 18:55 — user2357112, Jun 30 '17 at 18:55

score 1 · Accepted Answer · answered Jun 30 '17 at 18:56

1

L = [(2, 4), (8, 5), (1, 3), (9, 4), (3, 5)]
L[:] = sorted(L,key = lambda ratio: 1.*ratio[0]/ratio[1])
print L

answered Jun 30 '17 at 18:56

Ghilas BELHADJ

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`float(ratio[0])/ratio[1]`. Or better yet: `from __future__ import division`. – Martijn Pieters Jun 30 '17 at 18:56

Sort the list L by the ratio of the elements in the 2-tuples in place

1 Answers1