ENTER executes program instead of creating a newline

Asked Jun 30 '17 at 20:31

Active Jun 30 '17 at 21:07

Viewed 42 times

Following the book The C Programming Language by Kernighan and Ritchie, I am trying do the following exercise:

Exercise 1-12 Write a program that prints its input one word per line.

This is my code:

main(){

int b;

while( (b=getchar()) != EOF){

    if(b != ' ' || b != '\t' || b != '\n')
        putchar(b);

    if(b == ' ' || b == '\t' || b == '\n')
        printf("\n");
    }

}

My problem is that pressing ENTER to get a newline executes the code in stead of just giving me a newline in the console.

Should not just an EOF do this? Otherwise, the program works just fine.

Edit: This is not, as far as I understand, a duplicate of Why non-equality check of one variable against many values always returns true? Although I should have used "&&" and not "||", the problem remains. When I press ENTER in the console, the program is executed in stead of giving me a newline. Please correct me if I am wrong.

edited Jun 30 '17 at 21:07

asked Jun 30 '17 at 20:31

Akitirija

1

Logic problem, the first `if` should be `if(b != ' ' && b != '\t' && b != '\n')` – Pablo Jun 30 '17 at 20:33
Or, even better, skip the first `if` altogether, and instead attach an `else` block to the second. – John Bollinger Jun 30 '17 at 21:22

ENTER executes program instead of creating a newline

0 Answers0