I don't know what does this mean (x^y) ? in c++

Question

what is this function used for ? and it's not for the power function. :

    #include<iostream>

    using namespace std;

    int main(){

    int x,y;

    cout<<(x^y)<<endl;/* this is the unkown (X^Y)*/

    return 0;

    }

FYI, the behaviour of your program is undefined. So really in your example `cout<<(x^y)< — George, Jul 01 '17 at 12:23
Possible duplicate of [Why doesn't C++ have a power operator?](https://stackoverflow.com/questions/14626960/why-doesnt-c-have-a-power-operator) — , Jul 01 '17 at 12:23
I like to think of `A^B` as "flip every bit in A that is set to 1 in B". Easy to remember and it's also the most practical use case. — zett42, Jul 01 '17 at 14:22

Marco Luzzara · Accepted Answer · 2020-05-13T17:10:58.443

The ^ operator is the bitwise XOR. Take for example 6 and 12

6 in binary is: 110

12 in binary is: 1100

The xor follows this rule: "The first or the second but not both". What does it mean? Its truth table should make it clear:

A     B     A^B
0     0      0
0     1      1
1     0      1
1     1      0

You can see that the only 1-bits are those where or A or B (but not both) are set.

Back to the first example:

A    1100 => 12
B    0110 => 6
A^B  1010 => 10

score 2 · Answer 2 · answered Jul 01 '17 at 12:13

2

It's XOR. If you want more information about it see here https://en.wikipedia.org/wiki/Exclusive_or

answered Jul 01 '17 at 12:13

Nikita Davidenko

160
2
12

score 2 · Answer 3 · answered Jul 01 '17 at 12:21

Power function in c++ is

#include <math.h>
#include <iostream>
int main()
{
    int x, y;
    std::cout << "Give numbers " << std::endl;
    std::cout << "x = ";
    std::cin >> x;
    std::cout << "y = ";
    std::cin >> y;
    std::cout << "Result = " << pow(x, y) << std::endl;
    return 0;

}

Your version is XOR (logical operation) which is used to for example embedded systems etc.

I don't know what does this mean (x^y) ? in c++

3 Answers3