Why I m getting Unreported Exception

Question

can you please why error comes in line 13 as unreported exception ,must be caught pr declared to be thrown

class Demo {
    public static void main(String args[]) {
        try {
            int x = 43 / 0;
        } catch (ArithmeticException ob) {
            throw ob;
        }

        try {
            int x = 43 / 0;
        } catch (Exception ob) {
            throw ob;
        }
        Exception ob = new Exception();
        throw ob;
        // Line 13 unreported exception Exception; must be caught or declared to be thrown
    }
}

You need to add a `throws` clause to your main method declaration: `public static void main(String args[]) throws Exception {` — markspace, Jul 01 '17 at 14:07
@markspace he doesn't need a `throws` declaration because he's using `try/catch`. — Cardinal System, Jul 01 '17 at 14:09
@CardinalSystem in his try/catch, he throws the exception. That's where the problem comes in (it's not really a problem, but he has to declare it). I didn't test this but I believe that is the answer. — markspace, Jul 01 '17 at 14:11
@CardinalSystem I added throws Exception to main method then it compiles and runtime comes arithmatic exception in line 4 — chamina, Jul 01 '17 at 14:20

Gilad Green · Answer 1 · 2017-07-01T14:24:39.453

1

At the last line of your code you are throwing an exception but there is nothing handling it. You must do one of two:

Surround it with a try/catch block
Use the throws keyword in the method's signature. See this SO question: The throws keyword for exceptions in Java

In addition this question: Why is “throws Exception” necessary when calling a function?

Secondly after adding it the code will compile but when executed will still throw an exception:

Exception in thread "main" java.lang.ArithmeticException: / by zero

Reason is that in the catch blocks you are re-throwing the exception.

edited Jul 01 '17 at 14:24

answered Jul 01 '17 at 14:09

Gilad Green

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You mean adding throws in main method – chamina Jul 01 '17 at 14:23
@chamina - yes. to the main – Gilad Green Jul 01 '17 at 14:24

score 1 · Accepted Answer · answered Jul 01 '17 at 14:13

1

You need to add a throws to the method that throws exceptions as mentioned before as well as all the methods that call that method

answered Jul 01 '17 at 14:13

Karol Wojtulewicz

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Why I m getting Unreported Exception

2 Answers2