a = [[0, 0, 0]] * 3
print(a)
[[0, 0, 0], [0, 0, 0], [0, 0, 0]]
a[1][0] = 99
print(a)
[[99, 0, 0], [99, 0, 0], [99, 0, 0]]
here when I am trying to update a[1][0] every row automatically get updated how to overcome this
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idjaw
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Nikesh T T
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don't do this because lists are mutable. Do `[[0,0,0] for _ in range(3)]` – Jean-François Fabre Jul 04 '17 at 14:55
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Thank you very much - Jean-François Fabre – Nikesh T T Jul 14 '17 at 07:19