Not getting dynamic variable names PHP

Question

I want to print the values of variable but it prints 12 only

$str1="abhishek";
$str2="ashish";
for($i=1;$i<=2;$i++)
{
echo $str.$i;
}

Possible duplicate of [Dynamic variable names in PHP](https://stackoverflow.com/questions/9257505/dynamic-variable-names-in-php) — bugwheels94, Jul 04 '17 at 18:01
You're concatenating `$str` with `$i`. You really are only echoing `$i` (`1`, then `2`) and you should be getting undefined variable `$str` notices. — chris85, Jul 04 '17 at 18:04

score 4 · Answer 1 · answered Jul 04 '17 at 18:14

4

This is a better practice:

<?php 
$str = array("abhishek","ashish");

for($i=0; $i <= 2; $i++)
{
echo $str[$i].'<br>';
}
?>

answered Jul 04 '17 at 18:14

Lekens

score 1 · Accepted Answer · answered Jul 04 '17 at 18:00

1

Do this:

$str1="abhishek";
$str2="ashish";
for($i=1;$i<=2;$i++){
    echo ${"str".$i};
}

answered Jul 04 '17 at 18:00

Rajdeep Paul

2 Answers2