Check python var if int

Question

I am trying to get python to check if a certain variable is an int

    numbergames = input("Number of Games to Analyze: ")
valuenumber = True
while valuenumber == True:
    if numbergames == int:
        valuenumber = False
    if numbergames != int:
        numbergames = input("Please type a valid number: ")
print("Thanks")

The code is getting stuck and is not getting out of the loop even thought the number typed is an int.

`int` is a `type`, not an instance of an integer. use `isinstance(numbergames,int)` — David Zemens, Jul 07 '17 at 18:06
https://docs.python.org/3.6/library/functions.html#isinstance — Håken Lid, Jul 07 '17 at 18:07
For how to deal with user input, take a look at this question. https://stackoverflow.com/a/23294659/1977847 — Håken Lid, Jul 07 '17 at 18:08

score 0 · Accepted Answer · edited Jul 07 '17 at 18:31

In general, it is discouraged to use type() as identifying if an input is int, float, etc. This is because it does not register a subclass of int as an int.

Instead, use isinstance('var', (int, long)) which will give the right result expected. So your code will take the form of:

numberGames = input("Number of Games to Analyze: ")

while True:
    if isinstance( numberGames, (int, long) ):
        break
    else:
        numberGames = input("Please type a valid number: ")
print("Thanks")

You don't need the valueNumber variable because its only use is as a flag for the while loop. Instead, it could continue running indefinitely with True until it reaches break because the statement tells the program to exit the loop.

Check python var if int

1 Answers1