How do I escape %% in a batch file

Question

I'm echoing out line from a batch file into another file. I know that to escape % you need %% but i can't figure out the escape sequence for %%. The following is what I am trying to accomplish

echo something %%stuff > secondFile.txt

Resulting in

something %%stuff

I have tried the following patterns:

%%%%
^%^%
%%%

Possible duplicate of [Ignore percent sign in batch file](https://stackoverflow.com/questions/1907057/ignore-percent-sign-in-batch-file) — Sam Denty, Jul 07 '17 at 19:01
No, you have not tried `%%%%` in a batch file as this would result in `%%` literally; perhaps you tried it in command prompt directly? — aschipfl, Jul 08 '17 at 08:12

score 1 · Accepted Answer · answered Jul 07 '17 at 18:59

1

it's different on command line and in a batchfile.

On commandline: echo some %%stuff
in a batchfile: echo some %%%%stuff

answered Jul 07 '17 at 18:59

Stephan

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How do I escape %% in a batch file

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