How can I pass value out of anonoymous function

Question

I would like to sent response from node server to client instead of greeting the return value of function Stats.calculate(), but I cannot figure out how to do it.

router.post('/calc', (req, res) => {      
    request.get('a secret url api', (err,res,bodyJson) => {
        if(err) console.log('error');
        if(res.statusCode !== 200 ) console.log('error');
        Stats.calculate(bodyJson, req.body.firstVal, req.body.secondVal);
    });
    res.json({greeting: "ciao"});
});

Any suggestions?

does shifting `res.json({greeting: "ciao"});` inside `request.get` solves your problem? — Girdhari Agrawal, Jul 07 '17 at 21:22
[How do I return the response from an asynchronous call?](/questions/14220321/how-do-i-return-the-response-from-an-asynchronous-call) — Thomas, Jul 07 '17 at 21:29

Alberto Trindade Tavares · Accepted Answer · 2017-07-07T21:31:47.480

2

You can just call res.json inside the callback:

router.post('/calc', (req, res) => {      
    request.get('a secret url api', (err, response, bodyJson) => {
        if(err) console.log('error');
        if(response.statusCode !== 200 ) console.log('error');
        var statsResult = Stats.calculate(bodyJson, req.body.firstVal, req.body.secondVal);

        res.json({result: statsResult});
    });

});

edited Jul 07 '17 at 21:31

answered Jul 07 '17 at 21:24

Alberto Trindade Tavares

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It doesn't work. I am getting error: TypeError: res.json is not a function – xTomasM Jul 07 '17 at 21:28
1

@xTomasM check my edited answer now. The problem was because the "res" parameter in the request.get was overriding the "res" from router.post – Alberto Trindade Tavares Jul 07 '17 at 21:32
I only renamed the inner one to "response" – Alberto Trindade Tavares Jul 07 '17 at 21:32
1

You are my hero ;) It works! – xTomasM Jul 07 '17 at 21:35

How can I pass value out of anonoymous function

1 Answers1