How do I properly escape the path to come out of find to a new command argument?
#!/bin/bash
for f in $(find . -type f -name '*.flac')
do
if flac -cd "$f" | lame -bh 320 - "${f%.*}".mp3; then
rm -f "$f"
echo "removed $f"
fi
done
returns
lame: excess arg Island of the Gods - 3.mp3
Using a Bash for loop is not ideal for the results of find or ls. There are other ways to do it.
You may want to use -print0 and xargs to avoid word splitting issues.
$ find [path] -type f -name *.flac -print0 | xargs -0 [command line {xargs puts in fn}]
Or use -exec primary in find:
$ find [path] -type f -name *.flac -exec [process {find puts in fn}] \;
Alternative, you can use a while loop:
find [path] -type f -name *.flac | while IFS= read -r fn; do # fn not quoted here...
echo "$fn" # QUOTE fn here!
# body of your loop
done
