str_replace and using extra "

Question

Hello I am using the str_replace but in the comparity I am using extra " thus it is not working. how can I use extra " inside the str_replace

$errorAlerts = str_replace("Password found in list of "most common passwords", please choose a more secure password.", "{$record['c_pw']}", $errorsAndAlerts);

Thanks for your input

`str_replace('Password found in list of "most common passwords", please choose a more secure password.', "{$record['c_pw']}", $errorsAndAlerts);` ? — Albzi, Jul 11 '17 at 09:06
use surrounding single quotes instead of double quotes, or [escape your string](https://stackoverflow.com/questions/7999148/escaping-quotation-marks-in-php) — hassan, Jul 11 '17 at 09:06
Go learn some basics: http://php.net/manual/en/language.types.string.php — CBroe, Jul 11 '17 at 09:09

score 3 · Accepted Answer · answered Jul 11 '17 at 09:07

3

Either escape

$errorAlerts = str_replace("Password found in list of \"most common passwords\", please choose a more secure password.", $record['c_pw'], $errorsAndAlerts);

or use single quotes

$errorAlerts = str_replace('Password found in list of "most common passwords", please choose a more secure password.', $record['c_pw'], $errorsAndAlerts);

answered Jul 11 '17 at 09:07

Jirka Hrazdil

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Hi yea, While using either the \ or the single quotes I do not get errors but the str_replace does not work aka the comparison does not work. I am using a cms and this is the error it is giving out, but I have a multilingual website thus I wanted to replace it with the correct language but the comparison does not work. if you have any input as to why I would be grateful. – Emma Linnery Jul 11 '17 at 09:59
@EmmaLinnery: Btw you have two different variables mentioned in the code: `$errorAlerts` and `$errorsAndAlerts`. Could it be that you are saving the replaced text to the wrong variable? – Jirka Hrazdil Jul 11 '17 at 10:09
thank you sorry, $errorsAlerts = str_replace("Password found in list of \"most common passwords\", please choose a more secure password.", "ding dong", $errorsAlerts); It doesnt work. – Emma Linnery Jul 11 '17 at 10:15

RiggsFolly · Answer 2 · 2017-07-11T09:15:59.447

1

Us single quotes around a double quoted literal

$errorAlerts = str_replace('Password found in list of "most common passwords", please choose a more secure password.', 
                            $record['c_pw'], 
                            $errorsAndAlerts);

edited Jul 11 '17 at 09:15

answered Jul 11 '17 at 09:07

RiggsFolly

93,638
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Edison Biba · Answer 3 · 2017-07-11T09:13:33.980

You can use two methods here

Use \ to escape double quotes

$errorAlerts = str_replace("Password found in list of \"most common passwords\", please choose a more secure password.", {$record['c_pw']}, $errorsAndAlerts);

Or you can use singe quotes.

$errorAlerts = str_replace('Password found in list of "most common passwords", please choose a more secure password.', {$record['c_pw']}, $errorsAndAlerts);

To specify a literal double quote, escape it with a backslash ().

Here is a good reference from php page how to use single and double quotes. Check out link

str_replace and using extra "

3 Answers3