A way to output pyunit test name in setup()

Question

Is there a way in python for a pyunit test to output the test it's currently running. Example:

def setUp(self):
    log.debug("Test %s Started" % (testname))

def test_example(self):
    #do stuff

def test_example2(self):
    #do other stuff

def tearDown(self):
    log.debug("Test %s Finished" % (testname))

score 99 · Accepted Answer · edited Sep 07 '22 at 09:17

99

You can use self._testMethodName. This is inherited from the unittest.TestCase parent class.

def setUp():
    print("In method", self._testMethodName)

edited Sep 07 '22 at 09:17

RiveN

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answered Dec 22 '10 at 05:01

Tyler Hobbs

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Where's the documentation for this? – Cory May 12 '11 at 13:13
8

There's not any. As you might guess from the underscore prefix on the attribute name, this is an internal attribute that's not intended to be exposed. I do wish that there was a proper way to do this, though. – Tyler Hobbs May 13 '11 at 21:00

Young-hwi · Answer 2 · 2019-08-20T02:37:32.933

19

self.id().split('.')[-1]

You can find the Documentation at: http://docs.python.org/library/unittest.html#unittest.TestCase.id

edit: For 2.7 users, https://docs.python.org/2.7/library/unittest.html#unittest.TestCase.id

edited Aug 20 '19 at 02:37

answered Feb 19 '13 at 09:45

Young-hwi

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score 6 · Answer 3 · edited Sep 09 '14 at 07:49

6

You can usestr(self.id()).split()[4]. It could be found here http://docs.python.org/library/unittest.html#unittest.TestCase.id

edited Sep 09 '14 at 07:49

guettli

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answered Jul 04 '11 at 10:46

Xiao

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A way to output pyunit test name in setup()

3 Answers3

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