PHP array How do i get only value one

Question

I have problem in multidimensional array I have a PHP array as follows:

$array1 = array( 
1 => '01-Jul-2017',
2 => '02-Jul-2017',
3 => '03-Jul-2017',
4 => '04-Jul-2017',
5 => '05-Jul-2017',
...,
31 => '31-Jul-2017',);

$array2 = array( 
1 => '01-Jul-2017',
3 => '03-Jul-2017',
4 => '04-Jul-2017',
5 => '05-Jul-2017',
6 => '06-Jul-2017',
...,
30 => '31-Jul-2017');

foreach($array1 as $array_one) {
    foreach($array2 as $array_two) {
        if($array_one == $array_two) {
            echo 'write';
        } else {
            **I want to display that does not exist in $ array2 output 02-Jul-2017;**
        }
    }
}

How do i get just the value 02-Jul-2017

Use array_diff() Please read http://php.net/manual/en/function.array-diff.php — RJParikh, Jul 13 '17 at 04:08
this is the question `I want to display that does not exist in $ array2` for that use `array_diff($array1, $array2)` — ArtisticPhoenix, Jul 13 '17 at 04:09
Possible duplicate of [array\_diff() with multidimensional arrays](https://stackoverflow.com/questions/11821680/array-diff-with-multidimensional-arrays) — RJParikh, Jul 13 '17 at 04:11

score 1 · Answer 1 · answered Jul 13 '17 at 04:09

You can use array_diff() inbuilt function.

$array1 = array( 
1 => '01-Jul-2017',
2 => '02-Jul-2017',
3 => '03-Jul-2017',
4 => '04-Jul-2017',
5 => '05-Jul-2017');

$array2 = array( 
1 => '01-Jul-2017',
3 => '03-Jul-2017',
4 => '04-Jul-2017',
5 => '05-Jul-2017',
6 => '06-Jul-2017');

$result=array_diff($array1,$array2);
print_r($result);

OUTPUT

Array ( [2] => 02-Jul-2017 )

Let me know if it not works.

PHP array How do i get only value one

1 Answers1