Python 3: print('...'), do stuff, print('done') on the same line

Question

I'd like to print an update on what's processing, then process it, then print a 'done' statement. The code below prints "waiting ... done" after the 2 second sleep finishes. How can I get the first print statement to execute before the code between the print statements executes?

import time
print("waiting ...", end=" ")
time.sleep(2)
print("done")

score 1 · Accepted Answer · answered Jul 15 '17 at 21:01

1

It's buffered. You need to flush the buffer:

print("waiting ...", end=" ", flush=True)

answered Jul 15 '17 at 21:01

user2357112

260,549
28
431
505

Easy enough, thank you! – M. Thompson Jul 15 '17 at 21:15

Python 3: print('...'), do stuff, print('done') on the same line

1 Answers1