I am facing the same problem now, and using try-catch
does not solve my issue. I developed the code below in order to deal with that.
import pandas as pd
import numpy as np
class KFold(object):
def __init__(self, folds, random_state=None):
self.folds = folds
self.random_state = random_state
def split(self, x, y):
assert len(x) == len(y), 'x and y should have the same length'
x_, y_ = pd.DataFrame(x), pd.DataFrame(y)
y_ = y_.sample(frac=1, random_state=self.random_state)
x_ = x_.loc[y_.index]
event_index, non_event_index = list(y_[y == 1].index), list(y_[y == 0].index)
assert len(event_index) >= self.folds, 'number of folds should be less than the number of rows in x'
assert len(non_event_index) >= self.folds, 'number of folds should be less than number of rows in y'
indexes = []
#
#
#
step = int(np.ceil(len(non_event_index) / self.folds))
start, end = 0, step
while start < len(non_event_index):
train_fold = set(non_event_index[start:end])
valid_fold = set([k for k in non_event_index if k not in train_fold])
indexes.append([train_fold, valid_fold])
start, end = end, min(step + end, len(non_event_index))
#
#
#
step = int(np.ceil(len(event_index) / self.folds))
start, end, i = 0, step, 0
while start < len(event_index):
train_fold = set(event_index[start:end])
valid_fold = set([k for k in event_index if k not in train_fold])
indexes[i][0] = list(indexes[i][0].union(train_fold))
indexes[i][1] = list(indexes[i][1].union(valid_fold))
indexes[i] = tuple(indexes[i])
start, end, i = end, min(step + end, len(event_index)), i + 1
return indexes
I just wrote that code and I did not tested it exhaustively. It was tested only for binary categories. Hope it be useful yet.