How to convert between the byte format that looks like [8, 200, 1, 16] to the one that looks like b'\x08\xc8\x01\x10\xc8 in python

Question

I'm not sure what this type of byte array format is called in python:
Format A:
[8, 200, 1, 16, 200, 1, 24, 200, 1, 34, 21, 8, 1, 18, 17, 98, 97, 116, 116, 108, 101, 95, 116, 97]
but I'd like to convert it into this format (the name of which I’m also unsure of):
Format B:
b'\x08\xc8\x01\x10\xc8\x01\x18\xc8\x01"\x15\x08\x01\x12'

I know how to get from Format B to Format A:
import array data =b'\x08\xc8\x01\x10\xc8' print array.array('B', data)) but I'm unsure of how to get from Format A to Format B, and because I also don't know the names of either format, the google results I've gotten have been sparse.

I've found the answer you're looking for here: https://stackoverflow.com/questions/3470398/list-of-integers-into-string-byte-array-python array.array('B', data).tostring() — Jace J McPherson, Jul 19 '17 at 23:31

score 2 · Answer 1 · answered Jul 19 '17 at 23:36

Piece of cake in Python 3:

>>> L = [8, 200, 1, 16, 200, 1, 24, 200, 1, 34, 21, 8, 1, 18, 17, 98, 97, 116, 116, 108, 101, 95, 116, 97]
>>> bytes(L)
b'\x08\xc8\x01\x10\xc8\x01\x18\xc8\x01"\x15\x08\x01\x12\x11battle_ta'

If you're back on Python 2:

>>> L = [8, 200, 1, 16, 200, 1, 24, 200, 1, 34, 21, 8, 1, 18, 17, 98, 97, 116, 116, 108, 101, 95, 116, 97]
>>> str(bytearray(L))
'\x08\xc8\x01\x10\xc8\x01\x18\xc8\x01"\x15\x08\x01\x12\x11battle_ta'

How to convert between the byte format that looks like [8, 200, 1, 16] to the one that looks like b'\x08\xc8\x01\x10\xc8 in python

1 Answers1