warning: passing 'int *[10]' to parameter of type 'const int *const *' discards qualifiers in nested pointer types

Question

I have the following file aaa.c:

int Test(const int * const * int_array, int count) {
  int min = int_array[0][0];
  for (int i = 1; i < count; ++i) {
    if (min > int_array[i][0])
      min = int_array[i][0];
  }
  return min;
}

void test_Test(void) {
  int i[10] = { 0, 1, 2, 3, 4, 5, 6, 7, 8, 9 };
  int *pi[10] = { &i[0], &i[1], &i[2], &i[3], &i[4], &i[5],
    &i[6], &i[7], &i[8], &i[9] };
  Test(pi, 10);
}

When I compile it with gcc -c aaa.c, the following warning is produced:

% gcc -c aaa.c 
aaa.c: In function ‘test_Test’:
aaa.c:14:8: warning: passing argument 1 of ‘Test’ from incompatible pointer type 
        [-Wincompatible-pointer-types]
   Test(pi, 10);
        ^~
aaa.c:1:5: note: expected ‘const int * const*’ but argument is of type ‘int **’
 int Test(const int * const * int_array, int count) {
     ^~~~

Why? What qualifier was discarded? const int * const * int_array certainly doesn't discard any qualifiers that int ** would have.