C# Random Function only produces one value

Question

In this for loop I keep getting same value from my Random Function. How can I get the Random Function to be actually Random?

for (int i=0; i<50; i++){
Random random = new Random();
int randomSong = random.Next(0, songList.Count - 1);
var selectedSong = songList.ElementAt(randomSong);
}

Put `Random random = new Random();` outside the loop – Ofir Winegarten Jul 21 '17 at 13:09 — Ofir Winegarten, Jul 21 '17 at 13:09

Sefa Şahinoğlu · Answer 1 · 2017-07-21T13:17:44.263

0

You need to define Random outside of the loop.

var rand = new Random();
for (int x = 0; x<50;x++)
{
    var song = list.ElementAt(rand.Next(list.Count()));
}

edited Jul 21 '17 at 13:17

answered Jul 21 '17 at 13:11

Sefa Şahinoğlu

494
4
9

I will edit my answer. Some typo erorrs. – Sefa Şahinoğlu Jul 21 '17 at 13:17

C# Random Function only produces one value

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