Python ValueError: 'dictionary update sequence element #0 has length 4; 2 is required'

Question

I have created a method that fetches the data from the database, converts it into json format and returns the JSON response.

    def getEchoResource(self):
        try:
           row = self.cursor.execute("SELECT * FROM echo_resource_log WHERE DATE(last_update) = CURDATE();")
           if row:
              response = app.response_class(response=json.dumps(dict(self.cursor.fetchall())), status=200, mimetype='application/json')
              return response
        except MySQLdb.Error as e:
           logger.error("Error %d: %s" % (e.args[0],e.args[1]))
        except Exception, e:
           logger.error("Error : ", str(e))

The method throws this error message - ValueError: 'dictionary update sequence element #0 has length 4; 2 is required'

Trace -

>/app/worker/echo/apps/opsware_flask_rest_app/opsware_flask_rest_app/
 updateEchoResource.py(123)getEchoResource()
-> row = self.cursor.execute("SELECT * FROM echo_resource_log WHERE 
  DATE(last_update) = CURDATE();")
 (Pdb) n
 >/app/worker/echo/apps/opsware_flask_rest_app/opsware_flask_rest_app/
  updateEchoResource.py(124)getEchoResource()
-> if row:
 (Pdb) n
 >/app/worker/echo/apps/opsware_flask_rest_app/opsware_flask_rest_app/
  updateEchoResource.py(125)getEchoResource()
-> response = 
  app.response_class(response=json.dumps(dict(self.cursor.fetchall())), 
  status=200, mimetype='application/json')
 (Pdb) n
  ValueError: 'dictionary update sequence element #0 has length 4; 2 is 
  required'
 >/app/worker/echo/apps/opsware_flask_rest_app/opsware_flask_rest_app/
  updateEchoResource.py(125)getEchoResource()

row returned -

('n3pvap168', 'X2Linux_NSS', 'Contact does not exist in Contacts table', datetime.datetime(2017, 7, 21, 4, 27, 37))

Can you fetch one record from `cursor` and print it out and show it to us? — Ziyad Edher, Jul 21 '17 at 19:40
Are you sure this method is throwing the error? Please include a traceback (stack trace). — pts, Jul 21 '17 at 19:55

score 2 · Answer 1 · answered Jul 21 '17 at 19:56

A Python dictionary as you probably know is an unordered set of key-value pairs. So each entry in a dictionary must have one key and one value. What is happening here is that you are trying to convert a sequence of four objects into a dictionary as shown by your row (hence the error expected length 2, got length 4).

To fix this, you will need to convert your 4-length data structure into a 2-length one. This can be done by creating an array of length 2 and storing the string you want to use as a key in the 0-index of the array and the rest of your row in the 1-index. You might be able to achieve this using slicing.

questionto42 · Answer 2 · 2022-02-01T10:24:17.363

You likely have to zip() before you dict(), using:

dict(zip(...))

In your case, with many rows, try:

{dict(zip(row))
         for row in cursor.fetchall()}

I could not test this! You might change the code, especially I am not sure whether the dict comprehension will be accepted.

With this guess, it would make:

    def getEchoResource(self):
        try:
           row = self.cursor.execute("SELECT * FROM echo_resource_log WHERE DATE(last_update) = CURDATE();")
           if row:
              response = app.response_class(response=json.dumps({dict(zip(row))
             for row in cursor.fetchall()}), status=200, mimetype='application/json')
              return response
        except MySQLdb.Error as e:
           logger.error("Error %d: %s" % (e.args[0],e.args[1]))
        except Exception, e:
           logger.error("Error : ", str(e))

If that does not work, have a look at the following:

Displaying database results in Python Flask: ValueError: dictionary update sequence element #0 has length 6; 2 is required to see an example of how to zip the dict if such an error pops up
which was originally taken from Output pyodbc cursor results as python dictionary --> recommended!

Python ValueError: 'dictionary update sequence element #0 has length 4; 2 is required'

2 Answers2