String a="ABC";
a="BCD";
System.out.println(a); //BCD
What happens to "ABC"? Can someone explain me what will happen?
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Suraj Rao
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user2024334
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1It will print 'BCD' – bigbounty Jul 23 '17 at 05:09
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4Please learn the **basics of Java** before asking. – u32i64 Jul 23 '17 at 05:10
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3Simply, It is value will changed and will be BCD, Because you assign this value to it. And It will print BCD – Fady Saad Jul 23 '17 at 05:10
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1yes even I answered same but what happens to "ABC",,does it remain in constant pool or what.. I am not sure .. Please explain – user2024334 Jul 23 '17 at 05:10
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1Gets garbage collected – henrybbosa Jul 23 '17 at 05:12
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2Nothing happens unless it can be observed. – shmosel Jul 23 '17 at 05:12
2 Answers
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When you perform String a="ABC", your string literal get's automatically added to String pool. It's kept in string pool so that JVM can reuse it if it can be.
After this, the rules for garbage collecting of string is same as that of any other object. Before we assign any other object to a variable, if "ABC" was referenced by any other variable, then it will stay there in the pool.
Otherwise, if it's not referenced anymore, then it will get garbage collected the very next time GC runs.
Raman Sahasi
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