Need to reverse an integer array based on the input median

Question

Need to reverse an array of integers based on the input number For example :

Array be [1,2,3,4,5,6,7,8,9] and value of subset be N = 4 then the array after reversal will be [4, 3, 2, 1, 8, 7, 6, 5, 9]. if N = 3 then output should be [3,2,1,6,5,4,9,8,7]

Couldn't think of a proper logic with recursive method or with any looping concepts

@klutt I think he needs to reverse all subarray of size exactly `4` — Davide Spataro, Jul 24 '17 at 17:21
This is just an array reverse problem from start until N...unless the problem definition is wrong. — Santanu C, Jul 24 '17 at 17:24
I'm voting to close this question as off-topic because it is a homework question, but it does not include the required summary of the work done so far to solve the problem, nor a description of the difficulty encountered in solving it. — RealSkeptic, Jul 24 '17 at 17:27

score 1 · Accepted Answer · answered Jul 24 '17 at 17:54

1

Try below java code

public static int[] reverse(int[] a, int number) {
    // negative case
    if (number < 0) {
        return a;
    }
    // higher count than array length
    int size = number < a.length ? number : a.length;
    int[] b = new int[size];
    System.arraycopy(a, 0, b, 0, size);
    for (int i = b.length - 1; i >= 0; i--) {
        a[b.length - 1 - i] = b[i];
    }
    return a;
}

Array has index with each element so above loop code is simple and efficient.

answered Jul 24 '17 at 17:54

Sagar balai

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Thank you So much. This was I looking for . – SurajSr Jul 26 '17 at 20:42
thanks, you can vote for my answer – Sagar balai Jul 31 '17 at 07:07

Need to reverse an integer array based on the input median

1 Answers1