Property without getter in Kotlin

Question

How can I declare a property with a custom setter, but without getter in Kotlin? In Anko for example they do it like this:

var myProperty: Type
    @Deprecated(AnkoInternals.NO_GETTER, level = DeprecationLevel.ERROR) 
    get() = AnkoInternals.noGetter()
    set(value) { field = value; /* setter logic */ }

But it looks a bit hacky to me. Is this a right way to do so? If yes, then what about the case when a project doesn't have Anko dependency?

P.S. Let me be clear - I want to have no getter at all, rather than private getter

I thought objects were immutable in Kotlin. I'm new to the language, so I'm not sure. It's a more functional style, is it not? No, I'm wrong: https://kotlinlang.org/docs/reference/properties.html — duffymo, Jul 25 '17 at 19:19
Possible duplicate of [Private getter and public setter for a Kotlin property](https://stackoverflow.com/questions/38243085/private-getter-and-public-setter-for-a-kotlin-property) — zsmb13, Jul 25 '17 at 19:20
@zsmb13, nope, I don't intend to have a private getter, but rather no getter at all — arslancharyev31, Jul 25 '17 at 19:21
Still the same question, you're looking for a write-only property. Deprecating the setter is still the best way to go for this use case. — zsmb13, Jul 25 '17 at 19:22
@duffymo, I'm new as well, but I'm not sure whether properties are a feature of functional programming — arslancharyev31, Jul 25 '17 at 19:22
Functional programming means functions and immutable objects. That's the beauty of it: Everything is inherently thread safe and parallelizable. — duffymo, Jul 25 '17 at 19:24
Kotlin allows programming in procedural, object-oriented, and functional styles, you can mix them without any restrictions. — Miha_x64, Jul 26 '17 at 07:50

score 8 · Accepted Answer · edited Sep 21 '20 at 23:06

8

Deprecating the getter is still the only way to get the effect.

You don't need an Anko dependency, just use the @Deprecated annotation with an appropriate level.

edited Sep 21 '20 at 23:06

Tom

4,910
5
33
48

answered Jul 25 '17 at 21:42

voddan

31,956
8
77
87

score 1 · Answer 2 · answered Feb 17 '22 at 18:22

voddan's answer was great, but I can also supplement it with how I implemented it:

@get:Deprecated(message = "no.", level = DeprecationLevel.ERROR)
lateinit var property: Any

here I use the lateinit modifier and the @Deprecated annotation for the getter.

Property without getter in Kotlin

2 Answers2