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Could you help me with an advice? I'm doing some QA test and am testing a site. During the process, one by one windows in Chrome open and I'm trying to switch between these windows in Chrome. I don't succeed to switch to the third window. Can you help please? I'm using Pycharm and Selenium framework.

Here is the part of the Code where I ask your assistance:

second_login= webdriver.Ie()
second_login.maximize_window()
second_login.get('http://google.com')
print(second_login.title)
second_login.find_element_by_id('id1').click()
tab_now = second_login.window_handles[1]
second_login.switch_to.window(tab_now)
print(second_login.title)
log = second_login.find_element_by_id('id2')
log.send_keys('admin1')
pas=second_login.find_element_by_id('id3')
pas.send_keys('pas1')
logbutton=second_login.find_element_by_class_name('LoginButton')
logbutton.click()
second_login.implicitly_wait(3)
tab_after = second_login.window_handles[-1]
second_login.switch_to.window(tab_after)
second_login.find_element_by_id('id4').click()
print(second_login.title)

Thank you.

sochirca ilie
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1 Answers1

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As described here, you can do it by using window_handles and switch_to_window method.

Before clicking the link first window handle as

window_before = driver.window_handles[0]

Second window handle of newly opened window as

window_after = driver.window_handles[1]

I assume the third window would be 

driver.window_nandles[2]

Also take a look here, you can loop trough windows, just break on the 3rd window and do whatever you want:

for handle in driver.window_handles:
    driver.switch_to_window(handle)

Hope it helps.

Slav Kurochkin
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  • Thanks Slav, but I have another issue now, when I run the code, the first 2 windows are opening and for the third one here is the error I receive: window_now = second_login.window_handles[2] IndexError: list index out of range – sochirca ilie Jul 28 '17 at 07:54
  • Hi, what happens if you call again second_login.window_handles[1] – Slav Kurochkin Jul 28 '17 at 14:05